-3z(2z-2)=-6(z^2-2)-3(-3)

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Solution for -3z(2z-2)=-6(z^2-2)-3(-3) equation: 



-3z(2z-2)=-6(z^2-2)-3(-3)

We move all terms to the left:

-3z(2z-2)-(-6(z^2-2)-3(-3))=0

We multiply parentheses

-6z^2+6z-(-6(z^2-2)-3(-3))=0



We calculate terms in parentheses: -(-6(z^2-2)-3(-3)), so:

-6(z^2-2)-3(-3)

We add all the numbers together, and all the variables

-6(z^2-2)+9

We multiply parentheses

-6z^2+12+9

We add all the numbers together, and all the variables

-6z^2+21

Back to the equation:

-(-6z^2+21)



We get rid of parentheses

-6z^2+6z^2+6z-21=0

We add all the numbers together, and all the variables

6z-21=0

We move all terms containing z to the left, all other terms to the right

6z=21

z=21/6

z=3+1/2

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